Question
From the following figure find ;
(i) x
(ii) ∠ABC
(iii) ∠ACD
(i) x
(ii) ∠ABC
(iii) ∠ACD
✓
Answer
(i) In Quadrilateral ABCD,
x + 4x + 3x + 4x + 48° = 360°
12x = 360° – 48°
12x = 312
$x=\frac{312}{12}=26^{\circ}$
(ii) ∠ABC = 4x4 × 26 = 104°
(iii) ∠ACD = 180° - 4x - 48°
= 180° - 4 × 26° - 48°
= 180° - 104° - 48°
= 180° - 152° = 28°
x + 4x + 3x + 4x + 48° = 360°12x = 360° – 48°
12x = 312
$x=\frac{312}{12}=26^{\circ}$
(ii) ∠ABC = 4x4 × 26 = 104°
(iii) ∠ACD = 180° - 4x - 48°
= 180° - 4 × 26° - 48°
= 180° - 104° - 48°
= 180° - 152° = 28°
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