(B) It has to be kept away from dust as it decomposes in presence of dust. Thus, the option (B) is correct.
(C) Hydrogen peroxide can act as oxidizing as well as reducing agent. For example, in acidic medium, it oxidizes ferrous ions to ferric ions. $2 \mathrm{Fe}^{2+}+\mathrm{H}_{2} \mathrm{O}_{2}+2 \mathrm{H}^{+} \rightarrow 2 \mathrm{Fe}^{3+}+2 \mathrm{H}_{2} \mathrm{O}$
In acidic medium, hydrogen peroxide reduces HOCI to chloride ion. $\mathrm{HOCl}+\mathrm{H}_{2} \mathrm{O}_{2} \rightarrow \mathrm{H}^{+}+\mathrm{Cl}^{-}+\mathrm{H}_{2} \mathrm{O}+\mathrm{O}_{2}$
Thus, the option $C$ is incorrect.
(D) It decomposes on exposure to light to form water and oxygen. $2 \mathrm{H}_{2} \mathrm{O}_{2} \rightleftharpoons 2 \mathrm{H}_{2} \mathrm{O}+\mathrm{O}_{2}$
Thus, the option (D) is correct.
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$(I)$ both the complexes can be high spin
$(II)$ $Ni(II)$ complex can very rarely be low spin.
$(III)$ with strong field ligands, $Mn(II)$ complexes can be low spin.
$(IV)$ aqueous solution of $Mn ( II )$ ions is yellow in color.
Assertion $A$ : A solution of the product obtained by heating a mole of glycine with a mole of chlorine in presence of red phosphorous generates chiral carbon atom.
Reason $R$ : A molecule with 2 chiral carbons is always optically active.
In the light of the above statements, choose the correct answer from the options given below:
$(a)$ isoleucine
$(b)$ cysteine
$(c)$ lysine
$(d)$ methionine
$(e)$ glutamic acid