Question
From the ground state electronic configuration of the elements given below, pick up the one with highest value of second ionisation energy.
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$A$ and $B$ are :
Isomer $(P) \Rightarrow$ Can be prepared by Gabriel phthalimide synthesis
Isomer $(Q) \Rightarrow$ Reacts with Hinsberg's reagent to give solid insoluble in $NaOH$
Isomer (R) $\Rightarrow$ Reacts with $HONO$ followed by $\beta$-naphthol in $NaOH$ to give red dye.
Isomers $( P ),( Q )$ and $( R )$ respectively are
$(A)$ $\left[ FeF _{6}\right]^{3-}$
$(B)$ $\left[ Fe ( CN )_{6}\right]^{3-}$
$(C)$ $\left[ MnCl _{6}\right]^{3-}$ (high spin)
$(D)$ $\left[ Mn ( CN )_{6}\right]^{3-}$