MCQ
From the ground state electronic configuration of the elements given below, pick up the one with highest value of second ionization energy
- A$1s^2\, 2s^2 \,2p^6 \,3s^2$
- ✓$1s^2\,2s^2\, 2p^6 \,3s^1$
- C$1s^2 \,2s^2 \,2p^6$
- D$1s^2\, 2s^2 \,2p^5$
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${A_2}(g) + 4{B_2}(g) \rightleftharpoons 2A{B_4}(g)\,;\,\Delta H < 0$
the formation of $AB_4(g)$ will be favoured by

$(A)$ $SnCl _2 \cdot 2 H _2 O$ is a reducing agent.
$(B)$ $SnO _2$ reacts with $KOH$ to form $K _2\left[ Sn ( OH )_6\right]$.
$(C)$ A solution of $PbCl _2$ in $HCl$ contains $Pb ^{2+}$ and $Cl ^{-}$ions.
$(D)$ The reaction of $Pb _3 O _4$ with hot dilute nitric acid to give $PbO _2$ is a redoxreaction.