MCQ
From the ground state electronic configuration of the elements given below, pick up the one with highest value of second ionization energy
- A$1s^2\, 2s^2 \,2p^6 \,3s^2$
- ✓$1s^2\,2s^2\, 2p^6 \,3s^1$
- C$1s^2 \,2s^2 \,2p^6$
- D$1s^2\, 2s^2 \,2p^5$
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Compound $X$ and $Y$ are respectively.
$(A)$ Compounds $P$ and $Q$ are carboxylic acids.
$(B)$ Compound $S$ decolorizes bromine water.
$(C)$ Compounds $P$ and $S$ react with hydroxylamine to give the corresponding oximes.
$(D)$ Compound $R$ reacts with dialkylcadmium to give the corresponding tertiary alcohol.
$\Delta\text{S}(\text{C}\rightarrow\text{D})=30\text{ev},$
$\Delta\text{S}(\text{B}\rightarrow\text{D})=20\text{ev}$
$\text{A}\rightarrow\text{B}\\\downarrow\ \ \ \ \ \uparrow\\\text{C}\rightarrow\text{D}$
The entropy change for A → B would be:
