Question
From, $x^3-5 x^2+3 x+1$, take away $6 x^2-4 x^3+5+3 x$
✓
Answer
Required expression:
$=\left(x^3-5 x^2+3 x+1\right)-\left(6 x^2-4 x^3+5+3 x\right)$
$=x^3-5 x^2+3 x+1-6 x^2+4 x^3-5-3 x$
$=x^3+4 x^3-5 x^2-6 x^2+1-5$
$=5 x^3-11 x^2-4$
$=\left(x^3-5 x^2+3 x+1\right)-\left(6 x^2-4 x^3+5+3 x\right)$
$=x^3-5 x^2+3 x+1-6 x^2+4 x^3-5-3 x$
$=x^3+4 x^3-5 x^2-6 x^2+1-5$
$=5 x^3-11 x^2-4$
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