MCQ
$\text{f}(\text{x})=\sqrt{9-\text{x}^2}$. Find the domain of the function:
- A(0, 3)
- B(0, 3)
- C(-3, 3)
- D(-3, 3)
Solutuion:
We know radical cannot be negative.
So, $9-\text{x}^2,\geq 0$
$ (3 - \text{x}) (3 + \text{x}) ≥$
$\Rightarrow (\text{x} - 3) (\text{x} + 3) ≤ 0$
$ \Rightarrow \text{x} ∈ [-3,3].$
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