MCQ
$\text{f}(\text{x})=\sqrt{9-\text{x}^2}$. Find the domain of the function:
  • A
    (0, 3)
  • B
    (0, 3)
  • C
    (-3, 3)
  • D
    (-3, 3)

Answer

  1. (-3, 3)

Solutuion:

We know radical cannot be negative.

So, $9-\text{x}^2,\geq 0$

$ (3 - \text{x}) (3 + \text{x}) ≥$

$\Rightarrow (\text{x} - 3) (\text{x} + 3) ≤ 0$

$ \Rightarrow \text{x} ∈ [-3,3].$

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