MCQ
General solution of $eq^n\, 2tan\theta \, -\, cot\theta =\, -1$ is
- A$n\pi $
- ✓$n\pi \,-\, \pi /4$
- C$n\pi \,+\, \pi /4$
- DNone of these
$2 \tan ^{2} \theta+\tan \theta-1 =0$
$(2 \tan \theta-1)(\tan \theta+1) =0$
$\tan \theta =-1 $
$\theta= n \pi-\pi / 4$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| $\mathrm{x}$ | $-2$ | $-1$ | $3$ | $4$ | $6$ |
| $\mathrm{P}(\mathrm{X}=\mathrm{x})$ | $\frac{1}{5}$ | $\mathrm{a}$ | $\frac{1}{3}$ | $\frac{1}{5}$ | $\mathrm{~b}$ |
If the mean of $X$ is $2.3$ and variance of $X$ is $\sigma^{2}$, then $100 \sigma^{2}$ is equal to :