MCQ
Give the $IUPAC$ name of this compound
  • $3-(3-$ Bromo $-4-$ chlorocyclopentyl)cyclopropene
  • B
    $3-(3-$ chloro $-4-$ bromocyclopentyl) cyclopropene
  • C
    $2-(3-$ bromo $-4-$ chlorocyclopentyl) cyclopropene
  • D
    $2-(3-$ chloro $-4-$ bromocyclopentyl) cyclopropene

Answer

Correct option: A.
$3-(3-$ Bromo $-4-$ chlorocyclopentyl)cyclopropene
a

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Compound $(X)$ will be

Compound $(X)$ $\xrightarrow[{Pt}]{{5{H_2}}}$ 

Compound $(X)$ $\xrightarrow{{AgN{O_3}}}$ Precipitate

Compound $(X)$ $\xrightarrow[{M{e_2}S}]{{{O_3}}}$ $\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\,\,\,\,\,\,\,\,\,\,O\,\,\,\,} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {H - C - C{H_2} - C{H_2} - C - C - H} 
\end{array}$ $\begin{array}{*{20}{c}}
  {\,\,O\,\,\,\,\,\,O\,\,\,\,\,\,\,\,\,\,} \\ 
  {||\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,} \\ 
  {H - C - C - O - H} 
\end{array}$ $ + \begin{array}{*{20}{c}}
  {O\,\,\,\,\,\,\,} \\ 
  {||\,\,\,\,\,\,\,\,} \\ 
  {H - C - O - H} 
\end{array}$ $ + \begin{array}{*{20}{c}}
  {CHO} \\ 
  {|\,\,\,\,\,\,\,\,} \\ 
  {CHO} 
\end{array}$

Choose the pair of species in which oxidation number of nitrogen is same
The oxidation number of $Cr$ in ${K_2}C{r_2}{O_7}$ is
The percentage of ${N_2}$ in urea is about
Given below are two statements.

Statement $I:$ In the titration between strong acid and weak base methyl orange is suitable as an indicator.

Statement $II:$ For titration of acetic acid with $\mathrm{NaOH}$ phenolphthalein is not a suitable indicator.

In the light of the above statements, choose the most appropriate answer from the options given below:

In the equilibrium $N_2 + 3H_2$ $\rightleftharpoons$ $2NH_3 + 22$ $k\,cal,$ the formation of ammonia is favoured by
At $25^{\circ} C$ and $1\, atm$ pressure, the enthalpy of combustion of benzene$_{(l)}$ and acetylene$_{(g)}$ are $-3268 \,kJ\, mol ^{-1}$ and $-1300\, kJ\, mol ^{-1}$, respectively. The change in enthalpy for the reaction $3 C _{2} {H _{2}}_{(g)} \rightarrow C _{6} {H _{6}}_{(l)}$, is $.....\,kJ \,mol ^{-1}$
A base is dissolved in water yields a solution with a hydroxide ion concentration of $0.05$  $mol\,\,litr{e^{ - 1}}.$ The solution is
From the following bond energies :

$H - H$ bond energy $:\, 431.37 \,kJ\, mol^{-1}$
$C= C$ bond energy $:\, 606.10\, kJ \,mol^{-1}$
$C - C$ bond energy $:\, 336.49\, kJ\, mol^{-1}$
$C - H$ bond energy $:\, 410.50\, kJ\, mol^{-1}$

Enthalpy for the reaction,

$\begin{array}{*{20}{c}}
  {H\,\,\,\,H} \\ 
  {|\,\,\,\,\,\,\,\,|} \\ 
  {C = C} \\ 
  {|\,\,\,\,\,\,\,\,\,|} \\ 
  {H\,\,\,\,H} 
\end{array}\, + \,H - H\, \to \,\begin{array}{*{20}{c}}
  {H\,\,\,\,H} \\ 
  {|\,\,\,\,\,\,\,\,|} \\ 
  {H - C - C - H} \\ 
  {|\,\,\,\,\,\,\,\,\,|} \\ 
  {H\,\,\,\,H} 
\end{array}\,$

will be  .............. $\mathrm{kJ \,mol}^{-1}$

The surface of copper gets tarnished by the formation of copper oxide. $N _2$ gas was passed to prevent the oxide formation during heating of copper at $1250 K$. However, the $N _2$ gas contains $1$ mole $\%$ of water vapour as impurity. The water vapour oxidises copper as per the reaction given below:

$2 Cu ( s )+ H _2 O ( g ) \longrightarrow Cu _2 O ( s )+ H _2( g )$

$P _{ H _2}$ is the minimum partial pressure of $H _2$ (in bar) needed to prevent the oxidation at $1250 K$. The value of $\ln \left( p _{ H _2}\right)$ is. . . . .

(Given: total pressure $=1$ bar, $R$ (universal gas constant) $=8 JK ^{-1} mol ^{-1}, \ln (10)=2.3$. $Cu ( s )$ and $Cu _2 O ( s )$ are mutually immiscible.

At $1250 K : 2 Cu ( s )+1 / 2 O _2( g ) \longrightarrow Cu _2 O ( s ) ; \Delta G ^\theta=-78,000 J mol ^{-1}$

$H _2( g )+1 / 2 O _2( g ) \longrightarrow H _2 O ( g ) ; \Delta G ^\theta=-1,78,000 J mol ^{-1} ; G$ is the Gibbs energy)