Question
Give three rational numbers equivalent to: $\frac{-3}{4}$
✓
Answer
Given rational number is $\frac{-3}{4}.$So, the equivaient rational numbers are
$\frac{3\times2}{4\times2}=\frac{-6}{8},\frac{-3\times3}{4\times3}=\frac{-9}{12}$
and $\frac{-3\times4}{4\times4}=\frac{-12}{16}$
Hence, three equivalent rational numbers are,
$\frac{-6}{8},\frac{-9}{12}$ and $\frac{-12}{16}.$
$\frac{3\times2}{4\times2}=\frac{-6}{8},\frac{-3\times3}{4\times3}=\frac{-9}{12}$
and $\frac{-3\times4}{4\times4}=\frac{-12}{16}$
Hence, three equivalent rational numbers are,
$\frac{-6}{8},\frac{-9}{12}$ and $\frac{-12}{16}.$
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