Given A= ( ccc 4 & 2 & 5 2 & 0 & 3 -1 & 1 & 0 ), write the value … - Vidyadip

Question

Given $A=\left(\begin{array}{ccc}4 & 2 & 5 \\ 2 & 0 & 3 \\ -1 & 1 & 0\end{array}\right),$ write the value of det. $\left(2 A A^{-1}\right).$

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Answer

$\begin{array}{rlrl}\left|2 A A^{-1}\right| & =(2)^3 & {\left[\because A A^{-1}= I \right]} \\ & =8 &\end{array}$

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