MCQ
Given $E_{C{u^{2 + }}/Cu}^o = 0.34\,V\,,\,E_{C{u^{2 + }}/Cu}^o = 0.15\,V$ Standard electrode potential for the half cell $Cu^+/Cu$ is ............. $\mathrm{V}$
- A$0.38$
- ✓$0.53$
- C$0.19$
- D$0.49$
$E_1^o\, = \,0.15\,\,V;$ $\Delta G_1^o\, = \, - \,{n_1}E_1^oF$
$C{u^{2 + }}\, + \,2e\, \to \,Cu$
$E_2^o\, = \,0.34\,V;$ $\Delta G_2^o\, = \, - \,{n_2}E_2^oF$
On subracting eq.$(i)$ from eq. $(ii)$ we get
$C{u^ + }\, + \,{e^ - }\, \to \,Cu;$ $\Delta {G^o}\, = \,\Delta G_2^o\, - \,\Delta G_1^o\,$
$ - n{E^o}F\, = \, - \,({n_2}{E^o}F\, - \,{n_1}E_1^oF)$
${E^o}\, = \,\frac{{\,{n_2}{E^o}F\, - \,{n_1}E_1^oF}}{{nF}}$
$ = \,\frac{{\,2 \times 0.34 - 0.15}}{1}$
$=\,0.53\,V$
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