MCQ
Given $E^o _{Cr^{3+} / Cr} = - 0.72\, V, \,$$E^o _{Fe^{2+} / Fe} =-0.42 \,V.$ The potential for the cell
$Cr\, | \,Cr^{3+}_{(0.1\,M)}\,||\, Fe^{2+}_{(0.01\, M)}\,|\, Fe$ is ......... $V$
- A$-0.26$
- B$0.336$
- C$-0.339$
- ✓$0.26$
$Cr\, | \,Cr^{3+}_{(0.1\,M)}\,||\, Fe^{2+}_{(0.01\, M)}\,|\, Fe$ is ......... $V$
$=-0.42-(-0.72)-\frac{0.059}{6} \log \frac{(0.1)^{2}}{(0.01)^{3}}$
$=-0.42+0.72-\frac{0.059}{6} \log \frac{0.1 \times 0.1}{0.01 \times 0.01 \times 0.01}$
$=0.3-\frac{0.059}{6} \log \frac{10^{-2}}{10^{-6}}$
$=0.3-\frac{0.059}{6} \times 4$
$=0.30-0.0393=0.26 V$
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Final proudct of above reaction
| Column $-I$ | Column $-II$ | ||
| $(a)$ | $[Pt(NH_3)_3Cl]Br$ | $(P)$ | Coordination isomerism |
| $(b)$ | $[Cr(NH_3)_5(NCS)]^{+2}$ | $(Q)$ | Ionisation isomerism |
| $(c)$ | $[Co(H_2O)_6]Cl_3$ | $(R)$ | Linkase isomerism |
| $(d)$ | $[PtCl_4] [Pt(NH_3)_4]$ | $(S)$ | Hydrated isomerism |
$ -\mathrm{OCH}_3,-\mathrm{NO}_2,-\mathrm{CN},-\mathrm{CH}_3-\mathrm{NHCOCH}_3, $
$ -\mathrm{COR},-\mathrm{OH},-\mathrm{COOH},-\mathrm{Cl}$
$(I)\, [Ni(CN)_4]^{2-}\,\,\,(II)\, [NiCl_4]^{2-}\,\,\,(III)\,Ni(CO_4)\,\,\,$
$(IV)\, [Ni(H_2O)_6 ]^{2+}$