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Matrices — MATHS STD 12 Science — Question

Rajasthan BoardEnglish MediumSTD 12 ScienceMATHSMatrices1 Mark
Question
Given that $\left[\begin{array}{ll}1 & x\end{array}\right]\left[\begin{array}{cc}4 & 0 \\ -2 & 0\end{array}\right]=0$, the value of $x$ is :
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Answer

We have $\left[\begin{array}{ll}1 & x\end{array}\right]\left[\begin{array}{cc}4 & 0 \\ -2 & 0\end{array}\right]=0 $
$ \Rightarrow [1 \times 4+x \times(-2) 1 \times 0+x \times 0]=\left[0 0\right]$
$\Rightarrow 4-2 x=0 $
$\Rightarrow 4=2 x$
$ \Rightarrow x=2$

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