Question
✓
Answer
1. 24 m²
2. 3696 m²
3. No, with valid reasoning
● No, the area reserved under part 1 is not equal to the area reserved under part 2. Area under part 1 is 3696 m² whereas the area under part 2 is 3024 m²
2. 3696 m²
3. No, with valid reasoning
● No, the area reserved under part 1 is not equal to the area reserved under part 2. Area under part 1 is 3696 m² whereas the area under part 2 is 3024 m²
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
How many solution(s) of the equation 2x + 1 = x – 3 are there on the:
- Number line
- Cartesian plane?
The diameter of a copper sphere is 18cm. The sphere is melted and is drawn into a long wire of uniform circular cross-section. If the length of the wire is 108m, find its diameter.
Draw the graph of the following equation.
x = 4
x = 4
Find three rational numbers lying between $\frac{3}{5}$ and $\frac{7}{8}.$ How many rational numbers can be determined between these two numbers?
→D is any point on side AC of a $\triangle\text{ABC}$ with AB = AC. Show that CD > BD.
→The follwoing data give the number of boys of a particular age in a class of 40 students.
Calculate the mean age of the students.
| Age (in years) | 15 | 16 | 17 | 18 | 19 | 20 |
| Frequency (fi) | 3 | 8 | 9 | 11 | 6 | 3 |
A hemisphere of lead of radius 9cm is cast into a right circular cone of height 72cm. Find the radius of the base of the cone.
Prove that:
$\Big(\frac{1}{\text{x}^{\text{a}-\text{b}}}\Big)^{\frac{1}{\text{a}-\text{c}}}\times\Big(\frac{1}{\text{x}^{\text{b}-\text{c}}}\Big)^{\frac{1}{\text{b}-\text{a}}}\times\Big(\frac{1}{\text{x}^{\text{c}-\text{a}}}\Big)^{\frac{1}{\text{c}-\text{b}}}=1$
→$\Big(\frac{1}{\text{x}^{\text{a}-\text{b}}}\Big)^{\frac{1}{\text{a}-\text{c}}}\times\Big(\frac{1}{\text{x}^{\text{b}-\text{c}}}\Big)^{\frac{1}{\text{b}-\text{a}}}\times\Big(\frac{1}{\text{x}^{\text{c}-\text{a}}}\Big)^{\frac{1}{\text{c}-\text{b}}}=1$
Prove that:
$9^{\frac{3}{2}}-3\times5^0-\Big(\frac{1}{81}\Big)^{\frac{-1}{2}}=15$
→$9^{\frac{3}{2}}-3\times5^0-\Big(\frac{1}{81}\Big)^{\frac{-1}{2}}=15$
AB is a line segment and P is its mid-point. D and E are points on the same side of AB such that $\angle$BAD = $\angle$ABE and $\angle$EPA = $\angle$DPB.
Show that:
→Show that:
- $\triangle$DAP $\cong$ $\triangle$EBP
- AD = BE
