STD 11 - 3. Classification of elements and periodicity in properties — NEET STD 11 Science — Question

Assertion $A :$ Dipole-dipole interactions are the only non-covalent interactions, resulting in hydrogen bond formation.

Reason $R$ : Fluorine is the most electronegative element and hydrogen bonds in $HF$ are symmetrical.

In the light of the above statements, choose the most appropriate answer from the options given below.

$Toluene\,\, \xrightarrow[{2.\,{H^ + }}]{{1.\,KMn{O_4}/O{H^ - }}}I\xrightarrow{{SOC{l_2}}}II\xrightarrow{{N{H_3}}}III\xrightarrow{{OB{r^ - }}}IV$ is

$(1)$ $PtCl_4·5NH_3$                $(2)$ $PtCl_4·4NH_3$

$(3)$ $PtCl4·3NH_3$                  $(4)$ $PtCl4·2NH_3$