MCQ
${H_2}{O_2}$ on reaction with $PbS$ gives
- A$PbO$
- ✓$PbS{O_4}$
- C$Pb{O_2}$
- D$PbHS{O_4}$
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$Cu ( s )+2 Ag ^{+}( aq ) \rightleftharpoons Cu ^{2+}( aq )+2 Ag ( s )$
The equilibrium constant for the reaction.$\frac{1}{2} Cu ^{2+}( aq )+ Ag ( s ) \rightleftharpoons \frac{1}{2} Cu ( s )+ Ag ^{+}( aq )$ is $x \times 10^{-8}$. The value of $x$ is (Nearest Integer)
$Al{(OH)_3} + 2{H_3}P{O_3} \to Al(OH){({H_2}P{O_3})_2} + 2{H_2}O$