MCQ
${H_2}S$ is more acidic than ${H_2}O$, due to
  • A
    $O$ is more electronegative than $S$
  • $O - H$ bond is stronger than $S - H$ bond
  • C
    $O - H$ bond is weaker than $S - H$ bond
  • D
    None of these

Answer

Correct option: B.
$O - H$ bond is stronger than $S - H$ bond
b
(b)The acidity of hydrides of $VI$ group elements increase from top to bottom as the bond strength $X - H$ decrease from top to bottom

${H_2}O < {H_2}S < {H_2}Se < {H_2}Te$

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$\begin{matrix}
   O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   ||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   C{{H}_{3}}-C-OH+C{{H}_{3}}-OH\overset{cat.}{\longleftrightarrow}  \\
\end{matrix}\begin{matrix}
   O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   ||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   C{{H}_{3}}-C-O-C{{H}_{3}}+{{H}_{2}}O  \\
\end{matrix}$

The reaction of elemental $P_4$ and aqueous $NaOH$ gives