MCQ
$H_3BO_3$ is
- ✓Monobasic and weak Lewis acid
- BMonobasic and weak Bronsted acid
- CMonobasic and strong Lewis acid
- DTribasic and weak Bronsted acid
So, it can accommodate only one additional electron pair in its outermost shell. Thus, $\mathrm{H}_{3} \mathrm{BO}_{3}$ is monobasic weak Lewis acid.
$\underset{\text { Base }}{\mathrm{H}_{2} \mathrm{O}}$+$\underset{\text { Acid }}{\mathrm{B}(\mathrm{OH})_{3}} \longrightarrow\left[\mathrm{B}(\mathrm{OH})_{4}\right]^{-}+\mathrm{H}^{+}$
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End product of the reaction is


$2NOCl(g)\, \rightleftharpoons \,2NO(g)\, + \,C{l_2}(g)$
[Given : $K_P = 8 \times10^{12}\,atm$ at $500\,K$ use $R = 0.08\,L\,atm\,mol^{-1}\,K^{-1}$ ]