Question
Higher Order Thinking question What must be the temperature in Fahrenheit, so that it will be twice its value in Celsius?
✓
Answer
According to the question, $F =2 C$ and $C _1= C$
$F=\frac{9 C}{5}+32 \\2 c=\frac{9}{5} C+32 \\2 c-\frac{9}{5} c+32 \Rightarrow \frac{10 c-9 c}{5}=32+0 \\
\frac{1 c}{5}=32$
$1 C=32 \times 5$
$C=160^{\circ}$
$\therefore F=2 C=2 \times 160^{\circ}$
$F=320^{\circ}$
$F=\frac{9 C}{5}+32 \\2 c=\frac{9}{5} C+32 \\2 c-\frac{9}{5} c+32 \Rightarrow \frac{10 c-9 c}{5}=32+0 \\
\frac{1 c}{5}=32$
$1 C=32 \times 5$
$C=160^{\circ}$
$\therefore F=2 C=2 \times 160^{\circ}$
$F=320^{\circ}$
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