MCQ
Highest $pH =14$ is given by
- A$0.1\,M\,{H_2}S{O_4}$
- B$0.1\,M\,NaOH$
- ✓$1\,N\,NaOH$
- D$1\,N\,HCl$
$[O{H^ - }] = 1;\,\,pOH = 0$; $pH + pOH = 14$
$pH = 14 - 0 = 14$
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if one mole of each of $X$ and $Y$ with $0.05 mol$ of $Z$ gives compound $XYZ _{3}$. (Given : Atomic masses of $X , Y$ and $Z$ are 10,20 and $30 amu$, respectively). The yield of $XYZ _{3}$ is $.........g$.(Nearest integer)
