MCQ
Highest stable $Mn$ fluoride is $MnF_4$ where as highest $Mn$ oxide is $Mn_2O_7$ due to
- A$O$ atom is smaller the $F$.
- ✓Oxygen has ability to form multiple bonds
- C$Mn^{7+}$ does not exist
- D$F$ can not-stabilise higher oxidation states
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Total sum of oxygen atoms in Product $A$ and Product $B$ are .........
(Given atomic number $\mathrm{Sc}: 21, \mathrm{Ti}: 22, \mathrm{~V}: 23, \mathrm{Cr}$ : $24, \mathrm{Mn}: 25, \mathrm{Fe}: 26)$