MCQ
Highest stable $Mn$ fluoride is $MnF_4$ where as highest $Mn$ oxide is $Mn_2O_7$ due to
- A$O$ atom is smaller the $F$.
- ✓Oxygen has ability to form multiple bonds
- C$Mn^{7+}$ does not exist
- D$F$ can not-stabilise higher oxidation states
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$Compound\xrightarrow{{KMn{O_4}/{H^ \oplus }}}$
($A$) Formic acid
($B$) Formaldehyde
($C$) Benzaldehyde
($D$) Acetone
Choose the correct answer from the options given below :
