MCQ
$HO-CH_2CH_2CH_2CH_2-Br \xrightarrow{{KOH}} Product$, product is
- A$HO-CH_2CH_2CH_2-OH$
- ✓

- C$CH_3CH_2CH_2CH_2CH_2OH$
- D





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$E^o_{Fe^{3+} /Fe} = -0.036\,V,$ $E^o _{Fe^{2+} /Fe} = -0.439\,V$
The value of standard electrode potential for the change,
$Fe^{3+} (aq) + e^- \rightarrow Fe^{2+} (aq)$ will be ........ $V$.