MCQ
Homologue of $CH_3-Cl$ is
- A$CH_3-CH_2-Br$
- B$\begin{array}{*{20}{c}}
{C{H_3} - CH - I} \\
{\,|} \\
{\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$ - ✓$CH_3-CH_2-CH_2-Cl$
- D$CH_3-(CH_2)_5-F$
✓
Answer
Correct option: C.
$CH_3-CH_2-CH_2-Cl$
c
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