- ABy dehydrohalogenation
- BBy dehydrogenation
- ✓By dehydration with conc. ${H_2}S{O_4}$ at ${170\,^o}C$
- DBy reduction with hydrogen iodide
The reaction of ethene with steam to form ethanol can be reversed. This allows ethanol to be converted into ethene. This is called a dehydration reaction.
$\underset{Ethanol}{C _2 H _5 OH} \xrightarrow[160^{\circ}-170^{\circ} C]{Conc. H _2 SO _4} \underset{Ethene}{CH _2= CH _2}+ \underset{Water}{H _2 O}$
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$(a)$ $O_2^ - ,{O_2}$ $(b)$ ${N_2},N_2^ +$ $(c)$ $NO^+, NO^-$
Reason : The third ionization energy of $Mn$ is larger than that of $Cr$.
Statement $I$ :- Methyl orange is a weak acid.
Statement $II$ :- The benzenoid form of methyl orange is more intense/deeply coloured than the quinonoid form.
In the light of the above statement, choose the most appropriate answer from the options given below :-
$H_3PO_4$ $\xrightarrow{{600\,{\,^o}C}}(Y)$
$(X)$ and $(Y)$ is