Question
How does the potential difference change with the effect of the dielectric when the battery is kept disconnected from the capacitor?

Answer

  1. Decreases
Explanation:
When the dielectric slab is introduced between the plates, the induced surface charge on the dielectric reduces the electric field.
The reduction in the electric field results in a decrease in potential difference.
$\text{V}=\text{Ed}=\frac{\text{E}_0\text{d}}{\text{k}}=\frac{\text{V}_0}{\text{k}}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free