How is the integrated rate equation for the first order reaction … - Vidyadip

Question

How is the integrated rate equation for the first order reaction represented by considering the concentration of the product?

✓

Answer

The integrated rate equation for the first order reaction can be represented as,
$k=\frac{2.303}{t} \log _{10} \frac{[ A ]_0}{[ A ]_t}$ where $[ A ]_0$ is the initial concentration of the reactant (at time, $1=0$ ) and $[ A ]_t$ is that at time $t$. Consider the reaction, $A \rightarrow B$

If $a$ is the initial concentration of the reactant $A$ and $x$ is the concentration of the product $B$ after time $t$, then
$[ A ]_0=a$ and $[ A ]_t=a-x$ (for $A$ )
$\therefore k=\frac{2.303}{t} \log _{10}\left(\frac{a}{a-x}\right) \text {. }$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "Answer the following in one or two sentence." from Chemical Kinetics→Chemical Kinetics — all question types→Chemistry STD 12 Science question papers→Maharashtra Board STD 12 Science question papers→Maharashtra Board question paper generator→

Similar questions

How many moles of methylbromide are required to convert ethanamine to N, N-dimethyl ethanamine?

What is the action of nitrous acid on aniline?

How is van’t Hoff factor related to molecular mass of the substance ?

Identify ‘A’ and ‘B’ in the following reaction …………………………………. .

Calculate total moles after dissociation in $0.1\ M KCl$ solution and $0.05\ M$ aluminium sulphate solution. Hence, decide which of the two solutions will have higher freezing point depression.

Anhydrous sodium sulphate dissolves in water with the evolution of heat. What is the effect of temperature on its solubility?

Identify $A$ and $B$ in the following reaction:
$CH _3- Br + Mg \xrightarrow{\text { dry ether }} A + CO _2 \xrightarrow[ H ^+ / H _2 O ]{\text { dry ether }} B + Mg ( Br ) OH$

Oxygen forms only $OF_2$ with fluorine while sulphur forms $SF_6$. Explain. Why?

(a) Given: $2 NO _{2( g )}+ F _{2( g )} \rightarrow 2 NO _2 F$
Rate $= k \left[ NO _2\right]\left[ F _2\right]$
Hence the reaction is first order with respect to $NO _2$ and first order with respect to $F _2$
$\therefore$ Order of reaction $= n _{ NO 2}+ n _{ F 2}=1+1=2$

(b) Given :
$\begin{aligned}
& CHCl _{3( g )}+ Cl _{2( g )} \rightarrow CCl _{4( g )}+ HCl _{( g ),} \\
& \text { Rate }= k \left[ CHCl _3\right]\left[ Cl _2\right]^{1 / 2}
\end{aligned}$
Hence the reaction is first order in $CHCl _3$ and half order in $Cl _2$.
$\therefore$ Order of reaction
$= n _{ CHCl3 }+ n _{ Cl 2}=1+\frac{1}{2}=\frac{3}{2}$

(a) Order of the reaction $=2$
(b) The order of the reaction $=\frac{3}{2}$

→

How is benzophenone prepared from benzonitrile?