$\begin{array}{*{20}{c}}
H\\
|\\
{ClHC = HC - C - CH = CHCl}\\
|\\
{Cl}
\end{array}$
- A$1$
- B$2$
- C$3$
- ✓$4$
$\begin{array}{*{20}{c}}
H\\
|\\
{ClHC = HC - C - CH = CHCl}\\
|\\
{Cl}
\end{array}$

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(Atomic no. : $B = 5,S = 16,Ni = 28,Xe = 54$)
$A$. $\mathrm{Be} \rightarrow \mathrm{Be}^{-}$
$B$. $\mathrm{N} \rightarrow \mathrm{N}^{-}$
$C$. $\mathrm{O} \rightarrow \mathrm{O}^{2-}$
$D$. $\mathrm{Na} \rightarrow \mathrm{Na}^{-}$
$E$. $\mathrm{Al} \rightarrow \mathrm{Al}^{-}$
Choose the most appropriate answer from the options given below :
$\mathrm{HF}, \mathrm{H}_2, \mathrm{H}_2 \mathrm{~S}, \mathrm{CO}_2, \mathrm{NH}_3, \mathrm{BF}_3, \mathrm{CH}_4, \mathrm{CHCl}_3, \mathrm{SiF}_4$, $\mathrm{H}_2 \mathrm{O}, \mathrm{BeF}_2$
$X + \frac{1}{2}{O_2}\,\, \to \,\,XO + 90.8\,kJ$
It follows that the heat of reaction for the following process $M + XO$ $\rightleftharpoons$ $MO + X$ is given by......$kJ$