Question
How many electrons will be present in the subshells having ms value of $-\frac{1}{2}$ for n = 4?

Answer

Number of orbitals in the nth shell = n2
For n = 4
Number of orbitals = 16
If each orbital is taken fully, then it will have 1 electron with ms value of $-\frac{1}{2}.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Explain the free expansion of gas.
What will be value of (pKa + pKb) at 25°C?
The compound AgF2 is unstable compound. However, if formed, the compound acts as a very strong oxidising agent. Why?
What are the net charges on the left and right side of the following equations? Add electrons as necessary to make each of them balanced half reactions.
  1. $\text{NO}^-_310\text{H}^+\xrightarrow{\ \ \ \ \ \ }\text{NH}^+_4+3\text{3H}_2\text{O}$
  2. $\text{Cl}_2+4\text{H}_2\text{O}\xrightarrow{\ \ \ \ \ \ \ }2\text{ClO}^-_2+\text{8}\text{H}^+$
What do you meant by Redox titration? Explain.
At 700 K , equilibrium constant for the reaction :
$H _2(g)+ I _2(g) \rightleftharpoons 2 HI ( g )$
is 54.8 . If $0.5 mol L ^{-1}$ of $HI ( g )$ is present at equilibrium at 700 K , what are the concentration of $H _2(g)$ and $I _2(g)$ assuming that we initially started with $HI ( g )$and allowed it to reach equilibrium at 700 K ?
$\text{N}_2+\text{3H}_2\rightleftharpoons2\text{NH}_3+\text{Heat}$ What is the effect of increasing temperature on value of K?
1g of graphite is burnt in a bomb calorimeter in excess of oxygen at 298K and 1 atmospheric pressure according to the equation:

$\text{C(graphite)}+\text{O}_2(\text{g})\overrightarrow{\ \ \ \ \ \ \ }\ \text{CO}_2(\text{g})$

During the reaction, temperature rises from 298K to 299K. If the heat superb, of the bomb calorimeter is 20.7kJ/ K, then what is the enthalpy change for the shove reaction at 298K and 1atm?

 PbO and PbO2 react with HCl according to following chemical equations:

$2\text{PbO}+4\text{HCl}\xrightarrow{ \ \ \ \ \ \ \ }2\text{PbCl}_2+2\text{H}_2\text{O}$

$\text{PbO}_2+4\text{HCl}\xrightarrow{\ \ \ \ \ \ \ \ }\text{PbCl}_2+\text{Cl}_2+2\text{H}_2\text{O}$

Why do these compounds differ in their reactivity? 

What do you mean by significant figures?