Question
How many five-digit numbers formed using the digit 0, 1, 2, 3, 4, 5 are divisible by 5 if digits are not repeated?
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$1^2+4^2+7^2+\ldots \ldots+(3 n-2)^2=\frac{n}{2}\left(6 n^2-3 n-1\right)$