
- A$3$
- ✓$4$
- C$6$
- D$8$


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$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_2} = CH - C{H_2} - C - H}
\end{array} \to C{H_3} - C{H_2} - C{H_2} - C{H_2}OH$
$(I)$ ${H_2}(g) + \frac{1}{2}{O_2}(g) \to {H_2}O(l);$
$\Delta {H^o_{298\,K}} = - 285.9\,kJ\,mo{l^{ - 1}}$
$(II)$ ${H_2}(g) + \frac{1}{2}{O_2}(g) \to {H_2}O(g);$
$\Delta {H^o_{298\,K}} = - 241.8\,kJ\,mo{l^{ - 1}}$
The molar enthalpy of vapourisation of water will be.....$kJ\,mol^{-1}$
Time Rate (mole $litre^{-1}\,sec^{ -1}$ )
$0$ $2.8 \times {10^{ - 2}}$
$10$ $2.78 \times {10^{ - 2}}$
$20 $ $2.81 \times {10^{ - 2}}$
$30$ $2.79 \times {10^{ - 2}}$
The reaction is
