$\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - CH - COOH\xrightarrow{\Delta }}
\end{array}$
- A$2$
- B$4$
- ✓$3$
- D$1$
$\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - CH - COOH\xrightarrow{\Delta }}
\end{array}$
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$\left( 2 \right)\,{N_2}\left( g \right) + {O_2}\left( g \right) \rightleftharpoons 2NO\left( g \right)\,,\,{K_2}$
$\left( 3 \right)\,{H_2}\left( g \right) + \frac{1}{2}{O_2}\left( g \right) \rightleftharpoons {H_2}O\left( g \right)\,,\,{K_3}$
The equation for the equilibrium constart of the reaction
$2N{H_3}\left( g \right) + \frac{5}{2}{O_2}\left( g \right) \rightleftharpoons 2NO\left( g \right) + 3{H_2}O\left( g \right)$
$(K_4)$ in terms of $K_1 , K_2$ , and $K_3$ is
$C{H_3}C \equiv \,CC{H_3}\,\xrightarrow[{{\text{heat}}}]{{NaN{H_2}/{\text{inert solvent}}}}P$