Question
How many $\sigma$ and $\sigma-$bonds are present in $\text{CH}_2=\text{C}-\text{CH}=\text{CH}_2?$
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Answer
$\ \ \ \ \ \ \ \ \ {\text{H}\ \ \ \ \ \ \text{H} \ \ \ \ \text{H} \ \ \ \ \ \text{H}} \\\ \ \ \ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ | \ \ \ \ \ \ | \ \ \ \ \ \ \ | \\\ \text{H}-\text{C}=\text{C}-\text{C}=\text{C}-\text{H}$
There are 9 $\sigma-$bonds and $2\pi-$bonds.
Reason: Each single bond is sigma bond each double bond has $1\sigma$ and $1\pi$ bond.
There are 9 $\sigma-$bonds and $2\pi-$bonds.
Reason: Each single bond is sigma bond each double bond has $1\sigma$ and $1\pi$ bond.
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