STD 11 - 8.2 Organic chemistry isomerism — JEE STD 11 Science — Question

$(i)$ $P{b^{2 + }} > P{b^{4 + }},T{l^ + } < T{l^{3 + }}$         $(ii)$ $Bi^{3+} < Sb^{3+} , Sn^{2+} < sn^{4+}$

$(iii)$ $P{b^{2 + }} > P{b^{4 + }},B{i^{3 + }} > B{i^{5 + }}$     $(iv)$ $T{l^{3 + }} < I{n^{3 + }},S{n^{2 + }} > S{n^{4 + }}$

$(v)$ $S{n^{2 + }} < P{b^{2 + }},S{n^{4 + }} > P{b^{4 + }}$     $(vi)$ $S{n^{2 + }} < P{b^{2 + }},S{n^{4 + }} < P{b^{4 + }}$

(Atomic number of $\mathrm{Ga}=31$ )

$C{H_3} - C \equiv C - H\xrightarrow{{NaN{H_2}}}\xrightarrow{{C{H_3} - I}}(A)\xrightarrow{{Li/liq\,N{H_2}}}(B)$

$C{H_3} - C \equiv C - H\xrightarrow{{NaN{H_2}}}\xrightarrow{{C{H_3} - I}}(A)\xrightarrow[{Pd.CaC{O_3}}]{{{H_2}}}(C)$

$\mathrm{Zn}(\mathrm{s})+\mathrm{Cu}^{2+}(0.02 \mathrm{M}) \rightarrow \mathrm{Zn}^{2+}(0.04 \mathrm{M})+\mathrm{Cu}(\mathrm{s})$

$\mathrm{E}_{\text {cell }}=...... \,\times 10^{-2} \,\mathrm{~V} { (Nearest integer) }$

${\left[\text { Use }: \mathrm{E}_{\mathrm{Cu} / \mathrm{Cu}^{2+}}^{0}=-0.34\, \mathrm{~V}, \mathrm{E}_{2 \mathrm{n} / \mathrm{Zn}^{2+}}^{0}=+0.76 \,\mathrm{~V}\right.}$

$\left.\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059\, \mathrm{~V}\right]$