MCQ
How many structural isomers are possible for a compound with molecular formula ${C_3}{H_7}Cl$
- ✓$2$
- B$5$
- C$7$
- D$9$
✓
Answer
Correct option: A.
$2$
(a) Two isomers $C{H_3} - \mathop {\mathop {CH}\limits_{|\,\,\,\,} }\limits_{Cl} - C{H_3}$ and
$C{H_3} - C{H_2} - C{H_2}Cl$ are possible for ${C_3}{H_7}Cl$.
$C{H_3} - C{H_2} - C{H_2}Cl$ are possible for ${C_3}{H_7}Cl$.
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