Question
How will you bring about the following conversion in not more than two step?
Benzaldehyde to 3-Phenylpropan-1-ol.
Benzaldehyde to 3-Phenylpropan-1-ol.
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$\text{H}_3\text{C}-\text{C}\equiv\text{C}-\text{H}\ \ \ \ \xrightarrow{\text{Hg}^{2+},\text{ H}_2\text{SO}_4}$
There are two –NH2 groups in semicarbazide. However, only one is involved in the formation of semicarbazones.
$\text{CH}_3-\text{O}-\text{CH}_2-\text{CH}-\text{CH}_3\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$
Acetylation.
