Question
How will you bring about the following conversion in not more than two step?
Bromobenzene to 1-Phenylethanol.
✓
Answer
Bromobenzene to 1-Phenylethanol:
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH}\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\text{C}_6\text{H}_5\text{Br}\xrightarrow{\ \text{Mg/dry ether}\ }\text{C}_6\text{H}_5\text{MgBr}\xrightarrow[(\text{ii})\text{H}_3\text{O}^+]{(\text{i}) \text{CH}_3\text{CHO}}\text{C}_6\text{H}_5-\text{CH}-\text{CH}_3$
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