Question
How would you determine the standard electrode potential of the system Mg2+|Mg?

Answer

The standard electrode potential of Mg2+ | Mg can be measured with respect to the standard hydrogen electrode, represented by Pt(s), H2(g) (1atm) | H+(aq) (1M).
A cell, consisting of Mg | MgSO4 (aq 1M) as the anode and the standard hydrogen electrode as the cathode, is set up.
$\text{Mg}|\text{Mg}^{2+}(\text{aq, 1M})||\text{H}^+(\text{aq, 1M})|\text{H}_2(\text{g, 1 bar}),\text{Pt}_{(s)}$
Then, the emf of the cell is measured and this measured emf is the standard electrode potential of the magnesium electrode.
$\text{E}^\ominus=\text{E}^\ominus_\text{R}-\text{E}^\ominus_\text{L}$
Here, $\text{E}^\ominus_\text{R}$ for the standard hydrogen electrode is zero.
$\therefore\ \text{E}^\ominus=0-\text{E}^\ominus_\text{L}$
$=-\text{E}^\ominus_\text{L}$

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