MCQ
Hybridisation of central atom in $N{F_3}$ is
- ✓$s{p^3}$
- B$sp$
- C$s{p^2}$
- D$ds{p^2}$
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$A + B \to$ Product
If the concentration of $B$ is increased from $0.1$ to $0.3\, mole$, keeping the value of $A$ at $0.1\, mole$, the rate constant will be
$C{H_3} - \mathop {\mathop {C = }\limits_{|\,\,\,\,} }\limits_{C{l_{}}\,} \mathop {\mathop {C\, - }\limits_{|\,\,\,\,\,\,} }\limits_{C{H_3}\,} \mathop {\mathop {CH - \,}\limits_{|\,\,\,\,\,\,\,\,\,} }\limits_{{C_2}{H_5}\,} C{H_2} - C \equiv CH$
Match List-l with List-ll:
| List-l | List-ll |
| A. Coke | I. Used to cut and grind hard materials. |
| B. Diamond | II. Carbon atoms are all $sp _2$ hybridised |
| C. Fullerene | III. Used as a reducing agent |
| D. Graphite | IV. Cage like molecules |
Choose the correct answer from the options given below:
