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STD 11 - 4. Chemical bonding and molecular structure — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 11 - 4. Chemical bonding and molecular structure4 Marks
MCQ
Hybridization of central $I$ in $I_3^-$ that is
  • ✓
    $sp$
  • B
    $sp^2$
  • C
    $sp^3$
  • D
    $sp^3d$
✓

Answer

Correct option: A.
$sp$
a
To know the hybridization of Triiodide ion, we can use simple hybridization formula which is given as;

Number of Hybridization $=$ Valence electron $+$ monovalent $+$ (negative charge $)-($ positive charge $) / 2$

If we look at the iodine atoms there are seven valence electrons in its outer shell and two monovalent atoms are also present. Further, during the combination of Iodine with the two other lodine atoms, the central atom gains a negative charge whose value will be taken as 1 .

If we place or substitute the values according to the formula, we get

$7+1+2 / 2$

$=10 / 2$

$=5$

Therefore the hybridisation number is equal to $5$. Now we can say that hybridisation is $sp ^3 d$.

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