MCQ
Hydrogen bonding is formed in compounds containing hydrogen and
  • Highly electronegative atoms
  • B
    Highly electropositive atoms
  • C
    Metal atoms with $d-$orbitals occupied
  • D
    Metalloids

Answer

Correct option: A.
Highly electronegative atoms
(a)Hydrogen bond is formed when hydrogen is attached with the atom which is highly electronegative and having small radius.

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Similar questions

If $1\, mole$ of aqueous nitric acid is formed, calculate total heat released

$\left. \begin{gathered}
  {\text{4N}}{{\text{H}}_{3(g)}}{\text{ + 5}}{{\text{O}}_{2(g)}} \to {\text{ 4N}}{{\text{O}}_{(g)}}{\text{ +  6}}{{\text{H}}_{\text{2}}}{{\text{O}}_{{\text{(l)}}}} \hfill \\
  {\text{2N}}{{\text{O}}_{(g)}}{\text{ + }}{{\text{O}}_{2(g)}} \to {\text{2N}}{{\text{O}}_{2(g)}} \hfill \\
  {\text{3N}}{{\text{O}}_{2(g)}}{\text{ +  }}{{\text{H}}_{{\text{ 2}}}}{{\text{O}}_{(l)}} \to {\text{2H N}}{{\text{O}}_{3(aq)}}{\text{ +  N}}{{\text{O}}_{(g)}} \hfill \\ 
\end{gathered}  \right|\begin{array}{*{20}{c}}
  {\Delta H(kJ)} \\ 
  { - 904} \\ 
  { - 112} \\ 
  { - 140} 
\end{array}$

A reaction

$2NO + 2H_2 \longrightarrow N_2 + 2H_2O$

has following mechanism

Step $-I$ : $2NO \longrightarrow N_2O_2$

Step $-II$ : $N_2O_2 + H_2 \longrightarrow N_2O + H_2O$

Step $-III$ : $N_2O + H_2 \longrightarrow N_2 + H_2O$

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