MCQ
Hydrolysis of acetamide produces
- ✓Acetic acid
- BAcetaldehyde
- CMethylamine
- DFormic acid
✓
Answer
Correct option: A.
Acetic acid
a
(a)$\underset{\text{Acetamide}}{\mathop{C{{H}_{3}}-CO-N{{H}_{2}}}}\,\underset{{{H}_{2}}O}{\mathop{\xrightarrow{\text{Hydrolysis}}}}\,\underset{\text{Acetic}\,\,\text{acid}}{\mathop{C{{H}_{3}}COOH}}\,+N{{H}_{3}}$
(a)$\underset{\text{Acetamide}}{\mathop{C{{H}_{3}}-CO-N{{H}_{2}}}}\,\underset{{{H}_{2}}O}{\mathop{\xrightarrow{\text{Hydrolysis}}}}\,\underset{\text{Acetic}\,\,\text{acid}}{\mathop{C{{H}_{3}}COOH}}\,+N{{H}_{3}}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Assertion : When $NO$ reacts with $FeSO_4$, a brown coloured complex is formed.
→Reason : In the complex, the coordination number of $Fe$ is $6$.
Two mole of an ideal gas is expanded isothermally and reversibly from $1$ litre ot $10$ litre at $300\,K$. The enthalpy change (in $kJ$) for the process is .....$kJ$
→Formic acid is a weak acid and hydrochloric acid is a strong acid. It follow that the
Bhopal tragedy gas is :
What is the equilibrium expression for the reaction ${P_{4(s)}} + 5{O_{2(g)}}$ $\rightleftharpoons$ ${P_4}{O_{10(s)}}$
→The molecules represented by the above two structures are
$1, 2-$dibromoethane when heated with alcoholic potash gives
→Which of the following compound is the strongest base
Product of the reaction is
The order of stability of the following tautomeric compounds is
→$\mathop {\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_2} = C - C{H_2} - C - C{H_3}}
\end{array}}\limits_{(I)} \rightleftharpoons $
$\mathop {\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_3} - C - C{H_2} - C - C{H_3}}
\end{array}}\limits_{(II)} \rightleftharpoons $
$\mathop {\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_3} - C = CH - C - C{H_3}}
\end{array}}\limits_{(III)} $