MCQ
Identify $(C)$ product of following reaction ?
  • A

  • B


  • D

Answer

Correct option: C.

c

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Stability order of following carbocation is :

$(i)$ $\begin{array}{*{20}{c}}
  {\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}-CH_2} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,|} 
\end{array}} \\ 
  {C{H_3} - {C^ + }} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} 
\end{array}$

$(ii)$  $\begin{array}{*{20}{c}}
  {\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,|} 
\end{array}} \\ 
  {C{H_3} - {C^ + }} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{H}} 
\end{array}$

$(iii)$ $\begin{array}{*{20}{c}}
  {\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,|} 
\end{array}} \\ 
  {C{H_3} - {C^ + }} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} 
\end{array}$

$(iv)$ $Ph - CH ^{+}-\underline{ CH }_{3}$ 

The enthalpy and entropy change for the reaction :

$Br_{2(l)} + Cl_{2(g)} \rightarrow 2BrCl_{(g)}$

are $30\ kJ\ mol^{-1}$ and $105\ J\ K^{-1} mol^{-1}$ respectively. The temperature at which the reaction will be in equilibrium is ............... $\mathrm{K}$