- A$CHC{l_3} + {(C{H_3})_2}CO$
- B${(C{H_3})_2}CO + {C_6}{H_5}N{H_2}$
- C$CHC{l_3} + {C_6}{H_6}$
- ✓${(C{H_3})_2}CO + C{S_2}$
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Statement I : $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$ is a homoleptic complex whereas $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]^{+}$is a heteroleptic complex.
Statement II : Complex $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$ has only one kind of ligands but $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]^{+}$has more than one kind of ligands.
In the light of the above statements, choose the correct answer from the options given below.
($A$) can also be prepared by reaction of $\mathrm{P}_4$ and $\mathrm{HNO}_3$
($B$) is diamagnetic
($C$) contains one $\mathrm{N}-\mathrm{N}$ bond
($D$) reacts with $\mathrm{Na}$ metal producing a brown gas

when $\underset{(i)}{\mathop{\gamma =C{{H}_{3}}CO_{2}^{-},}}\,\,\,\,\,\,\underset{(ii)}{\mathop{Cl-C{{H}_{2}}-CO_{2}^{-},}}\,\,\,\,\,\,\,\underset{(iii)}{\mathop{Ph-SO_{3}^{-}}}\,$