MCQ
Identify the nonionisable octahedral complex among following
- ✓$Pt(NH_3)_2Cl_4$
- B$Pt(NH_3)_4Cl_3$
- C$Pt(NH_3)_4Cl_4$
- D$Pt(NH_3)_3Cl_4$
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$(A)$ Na and excess of $NH _3$
$(B)$ $K$ and excess of $O _2$
$(C)$ $Cu$ and dilute $HNO _3$
$(D)$ $O _2$ and $2$-ethylanthraquinol
| List $-I$ | List $-II$ | ||
|
$(a)$ |
$\begin{array}{*{20}{c}} {O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {R - C - Cl \to R - CHO} \end{array}$ |
$(i)$ |
$Br _{2} / NaOH$ |
| $(b)$ | $\begin{array}{*{20}{c}} {R - C{H_2} - COOH \to R - CH - COOH} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Cl} \end{array}$ |
$(ii)$ | $H _{2} / Pd - BaSO _{4}$ |
| $(c)$ | $\begin{array}{*{20}{c}} {O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {R - C - N{H_2} \to R - N{H_2}} \end{array}$ |
$(iii)$ | $Zn ( Hg ) /$ Conc. $HCl$ |
| $(d)$ | $\begin{array}{*{20}{c}} {O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {R - C - C{H_3} \to R - C{H_2} - C{H_3}} \end{array}$ |
$(iv)$ | $Cl _{2}$ / Red $P , H _{2} O$ |
Choose the correct answer from the options given below:
|
List$-I$ (Chemical Reaction) |
List$-II$ (Reagent used) |
| $(a)$ $\mathrm{CH}_{3} \mathrm{COOCH}_{2} \mathrm{CH}_{3} \rightarrow \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}$ |
$(i)$ $\mathrm{CH}_{3} \mathrm{MgBr} / \mathrm{H}_{3} \mathrm{O}^{+}$ $(1 .$ equivalent $)$ |
| $(b)$ $\mathrm{CH}_{3} \mathrm{COOCH}_{3} \rightarrow \mathrm{CH}_{3} \mathrm{CHO}$ | $(ii)$ $\mathrm{H}_{2} \mathrm{SO}_{4} / \mathrm{H}_{2} \mathrm{O}$ |
| $(c)$ $\mathrm{CH}_{3} \mathrm{C} \equiv \mathrm{N} \rightarrow \mathrm{CH}_{3} \mathrm{CHO}$ | $(iii)$ $\mathrm{DIBAL}-\mathrm{H} / \mathrm{H}_{2} \mathrm{O}$ |
| $(d)$ $\mathrm{CH}_{3} \mathrm{C} \equiv \mathrm{N} \rightarrow \mathrm{CH}_{3}CO\mathrm{CH}_{3}$ | $(iv)$ $\mathrm{SnCl}_{2}, \mathrm{HCl} / \mathrm{H}_{2} \mathrm{O}$ |
Choose the most appropriate match :