
- ✓$a$
- B$b$
- C$c$
- D$d$


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${\left[ {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,||} \\
{C{H_2} = N = O}
\end{array}} \right]^\Theta }$
Major product in the above reaction is
Assertion $(A)$: Cis form of alkene is found to be more polar than the trans form
Reason $(R)$: Dipole moment of trans isomer of $2$-butene is zero.
In the light of the above statements, choose the correct answer from the options given below :
$(A)$ $\Delta S _{ x \rightarrow z}=\Delta S _{ x \rightarrow y}+\Delta S _{ y \rightarrow z}$
$(B)$ $w_{x \rightarrow z}=w_{x \rightarrow y}+w_{y \rightarrow z}$
$(C)$ $w_{x \rightarrow z \rightarrow z}=w_{x \rightarrow y}$
$(D)$ $\Delta S _{x \rightarrow y \rightarrow z}=\Delta S _{x \rightarrow y}$
