MCQ
If $0.4\,gm\,\,NaOH$ is present in $ 1$ litre solution, then its $pH$ will be
- A$2$
- B$10$
- C$11$
- ✓$12$
$[{H^ + }] = {10^{ - 12}},\,\,pH = - \log [{H^ + }] = 12$
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$(I)\,\, AgNO_3$
$(II)\,\, CaCO_3$
$(III) \,\,Pb(NO_3)_2$
$(IV) \,\,Na_2CO_3$