Question
If $10^{2y} = 25,$ then $10^{-y}$ equals:
✓
Answer
We have to find the value of $10^{-y}$
Given that $10^{2y} = 25,$ therefore,
$10^{2y} = 25$
$(10^y) 2 = 5^2$
$(10^\text{y})^{2\times\frac{1}{2}}=5^{2\times\frac{1}{2}}$
$\frac{10^{\text{y}}}{1}=\frac{5}{1}$
$\frac{1}{5}=\frac{1}{10^\text{y}}$
$\frac{1}{5}=10^\text{y}$
Given that $10^{2y} = 25,$ therefore,
$10^{2y} = 25$
$(10^y) 2 = 5^2$
$(10^\text{y})^{2\times\frac{1}{2}}=5^{2\times\frac{1}{2}}$
$\frac{10^{\text{y}}}{1}=\frac{5}{1}$
$\frac{1}{5}=\frac{1}{10^\text{y}}$
$\frac{1}{5}=10^\text{y}$
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