Question
If $2 a+\frac{1}{2 a}=8$, find : $16 a^4+\frac{1}{16 a^4} C$
✓
Answer
$ 16 a^4+\frac{1}{16 a^4}=\left(4 a^2+\frac{1}{4 a^2}\right)^2-2.4 a^2 \cdot \frac{1}{4 a^2}$
$ =(62)^2-2$
$ =3844-2$
$ =3842$
$ =(62)^2-2$
$ =3844-2$
$ =3842$
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